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x2 + 2x - 3= x2 + 3x - x - 3= x(x + 3) - 1 (x + 3)= (x + 3) (x - 1)Let p(x) = x4 + 2x3 - 2x2 + 2x - 3We see thatp(-3) = (-3)4 + 2(-3)3 - 2(-3)2 + 2(-3)
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(Get CBSE Board Textbook Solutions for all subjects from Class 9 to 12. You can also get the CBSE Board's previous year's solved papers from here! You can get online resources for Book Store, Test Series, Prepare Assignment and Previous Year Solved Papers for free! This is an organization related to the education sector. That's why you should not waste your precious time and join Zigya, where
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Good practices towards conserving forest and wildlife are numerous. (i) Nowadays, many non-governmental organisations are working towards creating public awaren
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(Get CBSE Board Textbook Solutions for all subjects from Class 9 to 12. You can also get the CBSE Board's previous year's solved papers from here! You can get online resources for Book Store, Test Series, Prepare Assignment and Previous Year Solved Papers for free! This is an organization related to the education sector. That's why you should not waste your precious time and join Zigy
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Find CBSE, ICSE State Boards Textbook Solutions of Class 8 to 12 of all subjects. Read NCERT Textbooks Questions and Answers & Find Previous year solved papers.
(Get CBSE Board Textbook Solutions for all subjects from Class 9 to 12. You can also get the CBSE Board's previous year's solved papers from here! You can get online resources for Book Store, Test Series, Prepare Assignment and Previous Year Solved Papers for free! This is an organization related to the education sector. That's why you should not waste your precious time and join Zigya, where many other study materials related to edu
1
The conductivity (k) of the solution in a cell is the reciprocal of its resistivity.
 The quantity  1/2  is cell constant.
L --> Distance between 2 ele
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(Get CBSE Board Textbook Solutions for all subjects from Class 9 to 12. You can also get the CBSE Board's previous year's solved papers from here! You can get online resources for Book Store, Test Series, Prepare Assignment and Previous Year Solved Papers for free! This is an organization related to the education sector. That's why you should not waste your precious time and join Zigya, wher
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1. छोटा भाई और भी है। 2. ज़्यादा- से- ज़्यादा बोझ।
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(Get CBSE Board Textbook Solutions for all subjects from Class 9 to 12. You can also get the CBSE Board's previous year's solved papers from here! You can get online resources for Book Store, Test Series, Prepare Assignment and Previous Year Solved Papers for free! This is an organization related to the education sector. That's why you should not waste your precious time and join Zigya, where many other study materials related to education are available for free.)
(You can also prepare for SSC
1
Second law is the real law of motion. This can be proved by showing that first law and third law are contained in second law of motion.(i) First law is contain
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(Get CBSE Board Textbook Solutions for all subjects from Class 9 to 12. You can also get the CBSE Board's previous year's solved papers from here! You can get online resources for Book Store, Test Series, Prepare Assignment and Previous Year Solved Papers for free! This is an organization related to the education sector. That's why you should not waste your precious time and join Zigya
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लेखक ने लता की गायकी की निम्नलिखित विशेषताओं को उजागर किया है-

1. निर्मलता-लता की गायकी की एक प्रमुख विशेषता है-उसके स्वरों की निर्मलता। लता का जीवन की ओर देखने का जो दृष्टिकोण है, वही उसके गाने की निर्मलता में झलकता है।

2. स्वरों की कोमलता और मुग्धता-लता की गायकी के स्वरों में कोमलता और मुग्धता है। इसके विपरीत नूरजहाँ के गायन में एक मादक उत्तान दिखाई पड़ता था।

3. नादमय उच्चार-यह लता के गायन की एक अन्य प्रमुख विशेषता है। उसके गीत के किन्हीं दो शब्दों का अंतर स्वरों की आस द्वारा बड़ी सुंदर रीति से भरा रहता है और ऐसा प्रतीत होता कि वे दोनों शब्द विलीन होते-होते एक दूसरे में मिल जाते हैं।
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Friction is usually called a necessary evil. It means it is essential in the life and we will not able do any work without it.

Advantages of friction Disadvantages of friction
Keeps the object in position: by friction, the object can be placed at the position and shaped. Wear and tear of object: Due to friction, there is wear and tear of objects. Lubrication is used to allow the parts to move easier, moreover, prevents wear and tear.
Helps to move: Frictional forces helps to move the object by friction. It helps in running walking. With friction of feet/ shoes on the surface, help to spe
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It is given that:
∆ABC ~ ∆DEF
We know that the ratio of areas of two similar triangles is equal to the ratio of the squares of any two corresponding sides.
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(Get CBSE Board Textbook Solutions for all subjects from Class 9 to 12. You can also get the CBSE Board's previous year's solved papers from here! You can get online resources for Book Store, Test Series, Prepare Assignment and Previous Year Solved Papers for free! This is an organization related to the education sector. That's why you should not waste your precious time and join Zigya,
1
Let radius (r) = 5x and height (h) = 7x.Now. Volume = 550x = 1∴ The required radius = 5x = 5 x 1 = 5cm.
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(Get CBSE Board Textbook Solutions for all subjects from Class 9 to 12. You can also get CBSE Board's previous year's solved papers from here! You can get online resources for Book Store, Test Series, Prepare Assignment and Previous Year Solved Papers for free! This is an organization related to the education sector. That's why you should not waste your precious time and join Zigya, where many other study materials related to education are
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ICSE Textbook Solutions Resource Centre For Class 8 to 12. Download solved CBSE previous year papers, Solved sample papers, Pre-board papers. Students can download NCERT solutions for Class 8 to 12 - Zigya.

(Get CBSE, ICSE, and all State Boards textbook solutions for all subjects Class 8 to 12. You can also get the CBSE solved papers of the previous year from here! You can also prepare for SSC. Can also test SSC, and find the SSC Resource Centre! You can get resources online for free for NEET, NEET's previous year solved paper, and JEE, JEE Previous year solved papers! Students can also fi